Question

principle=640,rate=12 1/2 time=6 months, find the SI along with amount​

Answer 1

$\red{\bigstar}$ Simple Interest $\large\leadsto\boxed{\tt\green{Rs. \: 40}}$

$\red{\bigstar}$ Amount $\large\leadsto\boxed{\tt\green{Rs. \: 680}}$

• Given:-

Principal = Rs. 640

Rate = 12 ½% → 25/2 % p.a

Time = 6 months → 1/2 years

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• To Find:-

Simple Interest [ S.I ]

Amount [ A ]

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• Solution:-

❶

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We know,

$\purple{\bigstar}$ $\large\underline{\boxed{\bf\red{S.I = \dfrac{P \times R \times T}{100}}}}$

where,

S.I = Simple Interest

P = Principal

R = Rate

T = Time

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• Substituting in the Formula:-

➪ $\sf S.I = \dfrac{640 \times 25 \times 1}{100 \times 2 \times 2}$

➪ $\sf S.I = \dfrac{16000}{400}$

★ $\bf\pink{S.I = Rs. 40}$

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❷

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We know,

$\purple{\bigstar}$ $\large\underline{\boxed{\bf\red{Amount = P + S.I}}}$

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• Substituting in the Formula:-

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➪ $\sf Amount = 640 + 40$

★ $\bf\pink{Amount = Rs. 680}$

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Therefore, the S.I and Amount are Rs. 40 and Rs. 680 respectively.