print a table of seven by using c++
Answers
Answered by
0
#include<iostream.h>
#include<conio.h>
void main()
{
int i,no,table=1;
clrscr();
cout<<"Enter any num : ";
cin>>no;
clrscr();
cout<<"Table of "<<no;
for(i=1;i< =10;i++)
{
table=no*i;
cout<<" \n"<<table;
cout<<"\n";
}
getch();
}
This will u to get table of any no.
HOPE THIS WILL HELP
MARK THIS AS BRAINLIST.
#include<conio.h>
void main()
{
int i,no,table=1;
clrscr();
cout<<"Enter any num : ";
cin>>no;
clrscr();
cout<<"Table of "<<no;
for(i=1;i< =10;i++)
{
table=no*i;
cout<<" \n"<<table;
cout<<"\n";
}
getch();
}
This will u to get table of any no.
HOPE THIS WILL HELP
MARK THIS AS BRAINLIST.
Answered by
0
Print table of 7:
Output:
7
14
21
28
35
42
49
56
63
70
Explanation:
program:
#include <iostream> //defining header file
using namespace std;
int main() //defining main method
{
int n=7,i=1; //defining variable
while(i<=10) //defining loop for calculate table
{
cout<<n*i<<endl; //print value
i++; //increment the value of i
}
return 0;
}
Description of the code:
- In the above C++ language code, first header file include, then the main method is defined.
- In the next step. an integer variable "n and i", is declared in which we assign a value that is "7 and 1".
- Then, a while loop is declared, inside this loop a print method is used, that prints the multiple of sever and increment the value of i.
Learn more:
- Print table: https://brainly.in/question/15218629
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