Question

Print the pattern in python

A
B A
B A B
B A B A
B A B A B

pattern is also in attachment​

Answer 1

$\texttt{\textsf{\large{\underline{Solution}:}}}$

The correct pattern would be -

      B

    B A

   B A B

 B A B A

B A B A B

The co‎de -

str="BABAB"

n=len(str)

for i in range(n):

 print(" "*(n-i),end="")

 print(*str[:i+1],sep=" ")

In each row, there are (n - i) number of spaces where 'i' is the row number (starting with 0) and n is the number of rows. Using string multiplication, spaces are added.

Then, using string slicing, alphabets are displayed with a space in between.