Question

Pritha drew a parallelogram of which length of two diagonals are 6cm and 8cm and each
angle between two diagonals is 90°. Let us write the length of sides of parallelogram and
what type of parallelogram it is.​

Answer 1

Answer:

Both diagonals of parallelogram are given then take AC = 8cm and BD = 6m.

Steps of construction :

⇒  Draw a line segment AC = 8cm.

⇒  With center A and radius more than half of AC, draw arcs, one on each sides of AC.

⇒  With center B and same radius, draw arcs cutting the previous arcs P and Q respectively.

⇒ Join PQ which is perpendicular to BC and bisects BC at half.

⇒  Construct an angle 60∘ at O on both sides of AC that is above and below.

⇒ Then draw the line through an angles which will be passing through pint O.

⇒  Cut off OD = 3cm and OB = 3cm. Then we get DB = 6cm.

⇒  Join AD, DC, BC and BA.

Thus, ABCD is the required parallelogram.