Question

Prithvi ke Abhinav mein yuvak rekha hone ki kya Karan hai

Answer 1

आपका उत्तर ऊपर attatched है

Answer 2

Answer:

First, let us know the setup of the question.

For series :- \sf{R_{eq} = R_1 + R_2}R

eq

=R

1

+R

2

Where R1, R-eq and R2 are the resistances in the wires respectively.

Now, for Parallel combination :-

\sf{\dfrac{1}{R_{eq}} = \dfrac{1}{R_1} + \dfrac{1}{R_2}}

R

eq

1

=

R

1

1

+

R

2

1

Now, in this question, we need to deal with Parallel arrangement first, to evade complexity.

\sf{\dfrac{1}{R_{eq}} = \dfrac{1}{6} + \dfrac{1}{3}}

R

eq

1

=

6

1

+

3

1

\sf{\dfrac{1}{R_{eq}} = \dfrac{2+1}{6}}

R

eq

1

=

6

2+1

\sf{\dfrac{1}{R_{eq}} = \dfrac{3}{6}}

R

eq

1

=

6

3

\sf{\dfrac{1}{R_{eq}} = \dfrac{1}{2}}

R

eq

1

=

2

1

\sf{R_{eq} = 2 \text{\O}mega}R

eq

=2Ømega

Now, we can apply the formula for series combination, which will be

\sf{R_{eq} = R_1 + R_2}R

eq

=R

1

+R

2

\sf{R_{eq} = 2 + 1}R

eq

=2+1 (One from the question, other we determined previously)