Question

prive that Cos^2A (1+tan^2A)=1​

Answer 1

Answer:

☆To remember:

》$\ 1 + tan^{2}(\theta)\;= sec^{2}(\theta)$

》$\ cos(\theta) = \dfrac{1}{sec(\theta)}$

☆solution:

$\implies{\sf{cos^{2}\theta.(1+tan^{2}(\theta)}}$

$\implies{\sf{cos^{2}\theta.sec^{2}(\theta)}}$

$\implies{\sf{\dfrac{1}{sec^{2}(\theta)}.sec^{2}(\theta)}}$

$\implies{\bf{1}}$

Henced proved!

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♧hope it helps!♧

Answer 2

Step-by-step explanation:

Answer:

☆To remember:

》$\ 1 + tan^{2}(\theta)\;= sec^{2}(\theta)$

》$\ cos(\theta) = \dfrac{1}{sec(\theta)}$

☆solution:

$\implies{\sf{cos^{2}\theta.(1+tan^{2}(\theta)}}$

$\implies{\sf{cos^{2}\theta.sec^{2}(\theta)}}$

$\implies{\sf{\dfrac{1}{sec^{2}(\theta)}.sec^{2}(\theta)}}$

$\implies{\bf{1}}$

Henced proved!

---------------------------------

♧hope it helps!♧

muskan Joshi