prive that w,angular velocity = 2π/T
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we know actually linear velocity is
V = distance / time .....
So such that in the circular motion ....we know the there is angular displacement that is theta and the time taken is denoted by the T as the time period ..
thus we get the omega (w) = total angular displacement that is 2pi/ time period...
there fore w = 2pi/ T.....
V = distance / time .....
So such that in the circular motion ....we know the there is angular displacement that is theta and the time taken is denoted by the T as the time period ..
thus we get the omega (w) = total angular displacement that is 2pi/ time period...
there fore w = 2pi/ T.....
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Answer:
The answer is 2π÷T
Where T represents time period
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