Priya bought 50 kg of fruits consisting of Apple's and bananas. she paid twice as much per kg for the Apple's as she did for the banana. if Priya bought RS.1800 worth of Apple's and RS.600 worth bananas, then how many ksg of each frunit did she buy?
Answers
Answer:
No. of apples = 30kg
No.of bananas = 20kg
Step-by-step explanation:
Total kg of apples = x kg = Rs.a/kg = Rs.ax
Total Kg of bananas = y kg ==Rs.b/kg = Rs.yb
x+y = 50..........equation 1
Also, a=2b ........equation 2
Given, Rs.ax = 1800 ....eqution3
and Rs.yb=600...equation 4
From 2 and 3 : ax=1800
==>(2b)x=1800
Keep the value of x from equation 1
2b(50-y)=1800
==>100b-2by=1800
keep the value of yb=600
100b-2*600 = 1800
100b-1200=1800
100b=3000
b=30
=>a=60
since ax = 1800 ==> x = 30Kg
therefore = y=20kg.
Answer:
Total kg of apples = x kg = Rs.a/kg = Rs.ax Total Kg of bananas = y kg ==Rs.b/kg = Rs.yb x+y = 50. .equation 1 Also, a=2b ..equation 2 Given, Rs.ax = 1800 ..eqution3 and Rs.yb=600..equation 4 From 2 and 3: ax=1800 ==>(2b)x=1800 Keep the value of x from equation 1 2b(50-y)=1800 ==>100b-2by=1800 keep the value of yb=600 100b-2*600 = 1800 100b-1200=1800 100b=3000 b=30 =>a=60 since ax = 1800 ==> x = 30Kg therefore = y%3D20K%.