Math, asked by shivamrastogi0, 11 months ago

Priya invested rupees 183750 at an interest rate of 7.6 % per annum for 3 years if the interest is compounded annually the and why amount of the end at the end of second year

Answers

Answered by 27jenny
14
hєч mαtє✌✌
hєrє íѕ ur αnѕwєr ✍✍

●INTEREST = Interest is the price paid by a borrower for the use of a lender's money.

TYPE OF INTEREST----- there are 2 type of interest--
●Simple Interest
●Compound Interest

♥Simple Interest = Simple interest is the computed on the principal for the entire period of borrowing.
Formula -----
I = Pit
A = P + I
I = A - P

here
I = Amount of Interest
P = principal ( initial value of an investment)
A = Accumulated amount ( Final value of an investment)
i = Annual interest rate in decimal
t = time in years

♥Compound Interest = compound interest as the interest that accrues when earnings for each specified period of time added to the principal thus increasing the principal base on which subsequent interest is compound.

Formula -
A = p (1 + i)^n
where,
i = Annual rate of interest
n = Number of conversion period per year
INTEREST = An - P
or
= P ( 1 + i)^n - P

Let, move to ur Question -----

ɢɪᴠᴇɴ ----
ᴩ = 183750
ʀ = 7.6
ɴ = 3 yᴇᴀʀꜱ
ᴀᴍᴏᴜɴᴛ ᴀᴛ ᴛʜᴇ ᴇɴᴅ ᴏꜰ 2ɴᴅ yᴇᴀʀ = ???

ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ
A = p (1 + i)^ɴ
ᴀ = 183750 ( 1 + 0.076) ^ 2
= 183750 (1.076) ^2
= 183750 ( 1.157776)
= ₹212 ,741. 34

ʜᴏᴩᴇ ɪᴛ ʜᴇʟᴩꜱ ᴜ☺☺
ꜰᴇᴇʟ ꜰʀᴇᴇ ᴛᴏ ᴀꜱᴋ ᴀɴy qᴜᴇʀy❤❤

shivamrastogi0: Hyndai Si and CI on rupees 5000 at 20% per annum for 3 year
27jenny: si = 3000
27jenny: ci = 3640
Answered by 27Aarohi
2
ɢɪᴠᴇɴ ----
ᴩ = 183750
ʀ = 7.6
ɴ = 3 yᴇᴀʀꜱ
ᴀᴍᴏᴜɴᴛ ᴀᴛ ᴛʜᴇ ᴇɴᴅ ᴏꜰ 2ɴᴅ yᴇᴀʀ = ???

ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ
A = p (1 + i)^ɴ
ᴀ = 183750 ( 1 + 0.076) ^ 2
= 183750 (1.076) ^2
= 183750 ( 1.157776)
= ₹212 ,741. 34

ʜᴏᴩᴇ ɪᴛ ʜᴇʟᴩꜱ ᴜ☺☺
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