Question

Priyanka borrowed rs 25920 from ridhima at the rate of 8% simple interest per year she then returned the money after,3 years and 2 month did she give to ridhima in Total​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Amount=32,486.4\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given: }} \\ \tt: \implies Principal(p) = 25920 \: rupees \\ \\ \tt: \implies Rate\%(r) = 8\% \\ \\ \tt: \implies Time(t) = 3 \: years \: 2 \: months \\ \\ \red{\underline \bold{To \: Find: }} \\ \tt: \implies Total \: amount = ?$

• In the given question information given about Priyanka borrowed rs 25920 from ridhima at the rate of 8% simple interest per year she returned the amount after 3 years and 2 month

• We have to find the total amount priyanka have to give ridhima.

• According to given question :

$\circ \: \tt{Time = \frac{3 \times 12 +2}{12} = \frac{38}{12} \: years}\\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies S.I= \frac{p \times r \times t}{100} \\ \\ \tt: \implies S.I = \frac{25920 \times 8 \times \frac{38}{12} }{100} \\ \\ \tt: \implies S.I= \frac{25920 \times 8 \times 38}{12 \times 100} \\ \\ \tt: \implies S.I = \frac{7879680}{1200} \\ \\ \green{\tt: \implies S.I = 6566.4 \: rupees} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Amount = p + S.I\\ \\ \tt: \implies Amount =25920 + 6566.4 \\ \\ \green{\tt: \implies Amount =32,486.4 \: rupees}$

Answer 2

Given :-

• Principal = Rs.25920 = Money Borrowed .
• Rate = 8% per annum.
• Time = 3 years + 2 months = 3 + (2/12) = 3 + (1/6) = (19/6) years.

Solution :-

SI = ( P * R * T )/100

Putting values :-

→ SI = (25920 * 8 * 19 ) / (100 * 6)

→ SI = (432 * 8 * 19) / 10

→ SI = Rs.6566.4

So,

→ Amount = Principal + SI

→ Amount = 25920 + 6566.4

→ Amount = Rs.32486.4 .

Hence, Priyanka Has to Give Rs.32486.4 back.