Question

prmciple of potentiometer.
The back emf in the inductance coil is 200 V. When the current in the coil changes
from zero to 2A in 0.01 sec. Calculate the self inductance of the coil.
The photoelectric work function of tungsten is 4.5 ev. Calculate its threshold
wavelength.​

Answer 1

Answer:

Explanation:

Question (1)

The back emf in the inductance coil is 200 V. When the current in the coil changes  from zero to 2A in 0.01 sec. Calculate the self inductance of the coil.?

We are given:

Voltage of coil = 200 V\

Change in current = 2A

Time period "t" = 0.02 seconds

E.m.f of the coil = L(di / dt) = 200

E.m.f of the coil = L ( 2 - 0) / 0.01

E.m.f of the coil = 2 / 0.01 = 100

L = self inductance of the coil = ⊥ H.

Hence the self inductance of the coil is ⊥ H.

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