pro that√1-cosx/1+cosx=sinx/1+cosx
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LHS=√(1-cosx)(1+cosx)/(1+cosx)(1+cosx) {multiply both denominator and numerator by 1+cosx}
√/1-cos²x/(1+cosx)² {using identity (a+b)(a-b)=a²-b²}
√(sin²x/(1+cosx)²
sinx/1+cosx
Step-by-step explanation:
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