Question

Prob. 17. The controlling force in a spring loaded governor is 1500 N when radius of rotation is 200 mm and 887.5 N when radius of rotation is 130 mm. The mass of each ball is 8 kg. If the controlling force curve is a straight line, then find – (i) Controlling force when radius of rotation is 150 mm. (ii) The speed of the governor when radius of rotation is 150 mm. (iii) Increase in initial tension so that the governor is isochronous. (iv) Isochronous speed. (R.G.P.V., Nov./Dec. 2007)​

Answer 1

Explanation:

Given:

F = ar + b

1500 = 200a + b

887.5 = 130a + b

⇒ a = 8.75 N/mm

⇒ b = - 250 N

Now,

For isochronous governor, b = 0

F = mrω2 = ar

∴ a = mω2

8.75 × 1000 = 8ω2

ω = 33.07 rad/s

∴ N = 315.8 rpm

Answer 2

Answer:

250N

Explanation:

the value of F is 250