probabilities that a husband and wife will be alive 20 years from now is given by 0.8 and 0.9 respectively find the probability that in 20 years 1.both will alive 2.neither will alive 3.at least one will alive
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0
Answer:
3) At least 1 will alive
Step-by-step explanation:
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3
Answer:
Let A be the event that a husband will be alive after 20 yrs.
Let B be the event that a wife will be alive after 20 yrs.
Now, PA = 0.8; PB = 0.9
Now, PA = 1-PA = 1 - 0.8 = 0.2
Now, PB 1 - PB = 1 - 0.9 = 0.1
a.Probability that both of them are alive = PA . PB
= 0.8×0.9 = 0.72
b.Probability that none of them is alive = PA . pb
= 0.2×0.1 = 0.02
c.
Probability that at least one of them is alive
= 1 - 0.02 = 0.08
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