Probability
Class 10
•Please answer both the questions.
Answers
9) To find:
=> probability of getting 53 sundays in a leap year.
Solution:
Total Number of weeks in a Non leap year=366 years => 52 weeks and 2 random days.
Let A be the event of getting Sundays in leap year.
A = { ( sat,sun); (sun,mon)}
n (A) = 2
Total possibilities= n (S) = 7
Therefore P (A) = n (A)/ n (S) = 2/7
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10) x = 1,2,3
y = 1,4,9
To find:
• Probability that the product xy of the two numbers selected will be less than 9.
Solution:
Number of possible outcomes for x is 1,2,3
n (X) = 3
Number of possible outcomes for y is 1,4,9
n (Y)= 3
Total outcomes = 6
Probability that product of x and y is less than 9;
=6/9 = 2/3
Refer the attachment , hope it helps you!
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Answer:
To find:- Probability (x²< 2)
Total number of outcomes (random numbe x) = 5 (-2,-1,0,1,2)
To find the no. of favorable outcomes , find square of each outcome.
(-2)² = 4 ❌(not favorable)
(-1)² = 1 ✔️ (favorable)
(0)² = 0✔️(favorable)
(1)² = 1 ✔️ (favorable)
(2)² = 4 ❌(not favorable)
So, no. of favorable outcomes = 3
Probability (x²<2) = \frac{no.of favorable outcomes}{Total no. of outcomes}
Totalno.ofoutcomes
no.offavorableoutcomes
= \frac{3}{5}
5
3