Probability getting greater than 6
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When is die thrown Possible Outcomes are 1,2,3,4,5,6 So n(S) = 6
We require 6 so the desired even E is such that n(E) = 1
Therefore Probability of getting 6 = n(E)/ n(S) = 1/6
Probability of Getting greater than 6 is 0.
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