Question

probability-if p (A) =1/3 ,P(B)=1/4, and P (AUB)=4/13, Find P(Aintersection B)

Answer 1

P (AUB)=p (A)+P(B)-P(Aintersection B)
P(Aintersection B)=p (A)+P (B)-P (AUB)
                         =1/3+1/4-4/13
                         =(91-48)/(12x13)
                         =43/156