probability of
1) getting an even number
2)a multiple of 3
Answers
Answered by
0
Answer:
possible outcomes ={ 1,2,3,4,5,6} no.=6
favorable outcomes = {3,6} no.=2
∴Probability = no. of favorable outcomes / no. of possible outcomes
=2/6
= 1/3 (simplified)
Step-by-step explanation:
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Answered by
0
Answer:
a).
even number =2, 4,6
probability of even number=3/6=0.5
b). Here S = {1,2,3,4,5,6}
Let E be the event of getting the multiple of 3
Then, E = {3,6}
P(E) = n(E)/n(S) = 2/6 = 1/3
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