Question

Probability of a hitting the target is 4/5 and that of b hitting the target is 2/3 the both fire the target find the probaba atleast one of them hit the target

Answer 1

since the probability of hitting the target by A is 4/5

so probability of hitting not hitting the target will be 1/5

and probability of hitting the target by B is 2/3

so probability of not hitting the target by B is 1/3

so required probability that atleast one of them hit the traget = 1-(1/5×1/3)

=14/15