Math, asked by mitu3488, 11 months ago

Probability of a leap year having 53 friday

Answers

Answered by Anonymous
10

hi✌️✌️

A leap year consists of 366 days.i.e 52 weeks and 2 days remaining.

These 2 days can be any of the following:

(Mon, Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat),(Sat,sun).

The number of cases = 7.

The number of cases in which we get a Friday = 2.

The probability of getting 53 Fridays in a leap year = 2/7.

Hope this helps!

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