probability of a number divisible by 2 or 3
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probability is infinite as there are infinite numbers divisible by 2 or 3
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A natural number is divisible by 22 or 33, if it is divisible by 66. So, numbers divisible by 66 are {6,12,18,....,966,12,18,....,96}. So there are total 1616 numbers out of which 33 distinct number can be chosen in 16×15×14=n(A)16×15×14=n(A). Also,the total no of ways = 100×99×98=n(S)100×99×98=n(S).
Required probability=n(A)n(S)=41155n(A)n(S)=41155. Hope it helps
Anonymous:
question is find probabality of numbers divisible by 2 or 3
not 22 or 33
he will do what ever he want who are u to question him
i am questioning u
hey can you tell me the answer please
but i think the question is incomplete
i will
there are infinte numbers divisible by 2 or 3
mark my answer as the brainliest
then i will
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