Question

probability of an alphabet

Answer 1

Answer:

11111111111।।।।।।।।।।

Answer 2

$\huge\bold\pink{AnswEr⤵}$

The probability of each is 1/26. This way of counting is ok but cumbersome. Take any permutation and swap A with B, then you get a new permutation. That is, swapping A↔B (or A↔Z) gives us a bijection between th permutations with A before B and those with B before A.