Math, asked by nishu1109, 5 months ago

Probability of an event E + Probability of the event ‘not E'=???

Answers

Answered by yukti45538

1

Answer:

1 is the correct answer for the question

Answered by ajay8949

1

$\sf{probability \: of \: an \: event \:E + probability \: of \:} \\ \sf {an \: event \: not \: (E )}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boxed{\sf\red{P(E) + P( \bar{ E }) = \: 1}}$

$\sf\orange{please\:mark\:as\:brainliest............}$

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