Question

Probability of an event E + Probability of the event ‘not E'=???​

Answer 1

Answer:

1 is the correct answer for the question

Answer 2

$\sf{probability \: of \: an \: event \:E + probability \: of \:} \\ \sf {an \: event \: not \: (E )}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boxed{\sf\red{P(E) + P( \bar{ E }) = \: 1}}$

$\sf\orange{please\:mark\:as\:brainliest............}$