Math, asked by woacmission, 8 months ago

Probability of an event through double colour card experiment.

Answers

Answered by amitnrw
7

Given :  double colour card experiment

To Find : Probability of an event through double colour card experiment.

Solution:

Lets take  2 colors  

Red  and Yellow

Red color  =  R    Numbers

Yellow Color  = Y   Numbers

Total Card = R + Y

Probability of Drawing Red Card  = R/( R + Y)

Probability of Drawing Yellow Card  =Y/( R + Y)

Probability of Drawing 2 Red Cards  =  \dfrac{^R C_2}{^{R+Y}C_2}

Probability of Drawing 2 Yellow Cards  =  \dfrac{^YC_2}{^{R+Y}C_2}

Probability of Drawing 1 Yellow Card and 1 Red Card   =  \dfrac{^R C_1 . ^Y C_1 + ^Y C_1 . ^R C_1 }{^{R+Y}C_2}

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Answered by ashika251060
3

Answer:

Step-by-step explanation:

Probability

Objective

To set the idea of probability of an event through a double colour cards experiment.

Prerequisite Knowledge

1. Sample space and event.

2. Total number of possible outcomes.

3. Favourable outcomes.

4. Probability of an event = .

Material Required

A cardboard of size 18 cm x 18 cm, two colour papers say pink and blue, pair of

dice, empty box, pair of scissors, sketch pens, fevicol, etc.

Procedure

1. Paste different colour papers, blue and pink on both sides of the board, (such

that pink on one side and blue on another side)

2. Divide the board into 36 small squared cards.

3. Write all 36 possible outcomes obtained by throwing two dice, e.g., for the

outcome (4,5), write 4 on the blue side and 5 on pink side.

4. Cut and put all the cards into a box.

5. Now take out each card one by one without replacement and write the

observation in appropriate column.

Observation

1. Total number of possible outcomes =

2. Total number of favourable outcomes of sum 2 =

3. Total number of favourable outcomes of sum 3 =

4. Total number of favourable outcomes of sum 4 =

5. Total number of favourable outcomes of sum 5=

6. Total number of favourable outcomes of sum 6 =

7. Total number of favourable outcomes of sum 7 =

8. Total number of favourable outcomes of sum 8 =

9. Total number of favourable outcomes of sum 9 =

10.Total number of favourable outcomes of sum 10 =

Using formula calculate the required Probability of each event.

Sample space (when two dice are thrown)

Example: Number of favourable outcomes of sum of numbers 2=1

Total outcomes = 36

∴ Probability of sum of numbers is 2 =

Similarly find other probabilities for different outcomes of sum.

Result

Probability of an event =

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