Question

probability of at least two heads when tossing 4 coins is

Answer 1

Answer:-

Total outcomes:- {14}

HHHH,HHTH,HTHH,THHH,HHHT,HTTH,TTHH,HHTT,HTHT,HTTT,TTTH,THTT,TTHT,

TTTT

Favourable outcomes:-{9}

HHHH,HHTH,HTHH,THHH,HHHT,HTTH,TTHH,HHTT,HTHT

P(E) = favourable outcomes/total outcomes

P(E) = 9/14

Hope it helps :3

Answer 2

Answer

The probability we get exactly one head is the probability that we get anyone of the following four outcomes:

THTT ,  TTHT, HTTT, TTTH . Each has probability 1/16, so the probability to get exactly one head in four tips is 1/16+1/16+1/16+1/16 = 4/16 = 1/4

i hope this ans will help u ......

Step-by-step explanation: