Question

Probability of getting 1 when a dice is thrown once

Answer 1

Answer:

No. of favourable outcomes = 1

Total no. of outcomes =6

we know that; Probability = no. of favourable outcomes / no. of total outcomes

=1/6

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Høpe it helps!!!! ^_^ thnkuh

Answer 2

$\purple{\huge \mathtt{ \underline{ \fbox{ \: \pink{Solution} \red : \: \: }}}}$

Possible Outcomes are : 1 , 2 , 3 , 4 , 5 , 6

∴ Total number of posible outcomes = 6

&

∴ Favourable outcomes = 1

We know that ,

$\mathtt{\large \fbox{Probability = \frac{Number \: of \: favourable \: outcomes }{Total \: number \: of \: outcomes } }}$

Substitute the known values , we get

$\sf \hookrightarrow Required \: probability = \frac{1}{6}$

Hence , the required probability of getting 1 , when a dice is thrown once is 1/6