Question

probability of getting 53 fridays in a leap year

Answer 1

Answer:

complete weeks plus 2 days. Hence if the leap year begins on a Sunday, it will have 53 Sundays and Mondays and 52 other days of the week. Thus a leap year will have 53 Fridays if the year begins on a Thursday or Friday. The probability that a leap year begins on any day of the year is the same = 1/7.

Step-by-step explanation:

We have,

We have,A leap year days=366days

We have,A leap year days=366daysThen, number of weeks=

We have,A leap year days=366daysThen, number of weeks= 7

We have,A leap year days=366daysThen, number of weeks= 7366

We have,A leap year days=366daysThen, number of weeks= 7366

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2days

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,52weeks=52fridays

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,52weeks=52fridaysMay be 2days=(Mon,Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat)(Sat,Sun),(Sun,Mon)

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,52weeks=52fridaysMay be 2days=(Mon,Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat)(Sat,Sun),(Sun,Mon)Then, total number of outcomes =7

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,52weeks=52fridaysMay be 2days=(Mon,Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat)(Sat,Sun),(Sun,Mon)Then, total number of outcomes =7Favorable Outcomes =2

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,52weeks=52fridaysMay be 2days=(Mon,Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat)(Sat,Sun),(Sun,Mon)Then, total number of outcomes =7Favorable Outcomes =2∴Probability required =

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,52weeks=52fridaysMay be 2days=(Mon,Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat)(Sat,Sun),(Sun,Mon)Then, total number of outcomes =7Favorable Outcomes =2∴Probability required = 7

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,52weeks=52fridaysMay be 2days=(Mon,Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat)(Sat,Sun),(Sun,Mon)Then, total number of outcomes =7Favorable Outcomes =2∴Probability required = 72

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,52weeks=52fridaysMay be 2days=(Mon,Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat)(Sat,Sun),(Sun,Mon)Then, total number of outcomes =7Favorable Outcomes =2∴Probability required = 72

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,52weeks=52fridaysMay be 2days=(Mon,Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat)(Sat,Sun),(Sun,Mon)Then, total number of outcomes =7Favorable Outcomes =2∴Probability required = 72

We have,A leap year days=366daysThen, number of weeks= 7366 =52week+2daysSo,52weeks=52fridaysMay be 2days=(Mon,Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat)(Sat,Sun),(Sun,Mon)Then, total number of outcomes =7Favorable Outcomes =2∴Probability required = 72 Hence, this is the answer.

Answer 2

Answer:

HEY THERE,

The probability is 2/7.

I hope this is helpful,

please mark as brainlist.