Probability of getting 6 in single throw of a die is
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The probability of getting either 1 or 2 or 3 or 4 or 5 when one dice is thrown is 5/6 x 5/6 x 5/6 for 3 dices = 125/216.
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Let p be the probability of getting a 6 in a throw of dice. Then p=16.p=16. Then, probability (q) of not getting a 6 is 1−p=561−p=56
Hence, probability of getting no 6 in a single throw of 3 dice is q3=(56)3=125216q3=(56)3=125216
So, the required probability of getting at least one 6 is 1−125216=912161−125216=91216.
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