Probability of getting a head when two coins tossed together
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S= {HH, TH, HT, TT}
n(s) =4
A= {HH, TH, HT}
n(A) = 3
P(A) =n(s) /n(A)
P(A) = 3/4
n(s) =4
A= {HH, TH, HT}
n(A) = 3
P(A) =n(s) /n(A)
P(A) = 3/4
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