Question

Probability of getting at least one head in 2 tosses

Answer 1

Answer:

2 is the probability of getting 1 head in 2 tosses

Answer 2

Step-by-step explanation:

E6 = {HT, TH, HH} and, therefore, n(E6) = 3. Therefore, P(getting at least 1 head) = P(E6) = n(E6)/n(S) = ¾.