Probability of getting at most one head in two coin tosses
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S = {HH, HT, TH, TT}
If A is the event obtaining at most 1 “Head” outcome, then the set of outcomes that makes up event A is
A = {(HT), (TH), (TT)}
Hence, the probability of event A is
P(A) = 3/4 = 0.75
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