Probability of getting containing blue ball is 2/ 3, from a bag containing 6 blue balls and 3 red balls, 12 red balls are added in the bag & then find the probability of getting
(a) a blue ball
(b) a red ball
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Answer:
(a) a blue ball ----- 2/7
(b) a red ball ------ 5/7
Step-by-step explanation:
At first ,
no. of blue balls = 6
no. of red balls = 3
so ....
after adding , total no. of balls = 9
Next , it is said that ,
12 red balls are added ...
then....
Total no. of red balls = 3+12 =15
and total no of balls in the bag =9+12=21
then ....
for Q.(a)
probability of getting a blue ball =
no. of blue balls / total no. of balls in the bag = 6/21 = 2/7
for Q.(b)
probability of getting a red ball =
no. of red balls / total no. of balls in the bag = 15/21 = 5/7
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