probability of getting even numbers in a single throw of die
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1/2 because there are only 3 even numbers out of 6 in a single throw of die
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Assume S={1,2,3,4,5,6}.
Let all outcomes are equally likely(fair dice).
Hence Probability of any one outcome occurring= 1/6.
The event that we get an even number on tossing the die can occur in 3 possible ways. Let E denote this event.
E= {2,4,6}
Now P(E)= 3*1/6= 1/2
Let all outcomes are equally likely(fair dice).
Hence Probability of any one outcome occurring= 1/6.
The event that we get an even number on tossing the die can occur in 3 possible ways. Let E denote this event.
E= {2,4,6}
Now P(E)= 3*1/6= 1/2
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