Question

Probability of getting head when a coin is always tossed twice a time

Answer 1

Hi baby

Step-by-step explanation:

Probability is defined as the number of favourable outcomes devided by the total number of outcomes.

In a coin tossing experiment, I have two outcomes ie. heads or tails.

If I want to know the probability of getting a head, my favourable outcome is gettin a head while my total outcomes are getting a head or getting a tail.

So probability of getting a head after my first coin toss is 1/2 (H/T,H). Let's call this -

P (1st toss) = 1/2

Now consider me tossing the same coin for the second time.

On the second coin toss, using the logic explained above, my probability of getting heads is again 1/2. Let's call this

P (2nd toss) =1/2

Now the original question asks the probability of getting two heads in two coin toss or if I may restate the question as “ what is the probability of getting continues heads in first *and second coin toss ?”

P (continues head in two toss) = Prob (1st toss) * Prob (2nd toss)

This gives me a probability of 1/4

Note: *i have multiplied the probability since the question has an *and condition. Always multiply when there is “and”.

Hope this helps!