Question

probability of getting neither a red card nor queen​

Answer 1

16/52=4/13

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Answer 2

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total outcomes = 52

favourable outcomes = 52 - (26+2)

¡.e = 52 - 28

¡.e = 24

$probability = \frac{favourabe \: outcomes}{total \: outcomes}$

¡.e

$p = \frac{24}{52}$

»

$p = \frac{12}{26}$

»

$p = \frac{6}{13}$