Probability of getting three heads when three coin are simultaneosuly tossed.
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Answer:
When 3 unbiased coins are tossed once. And, therefore, n(S) = 8. and, therefore, n(E1) = 1. Therefore, P(getting all heads) = P(E1) = n(E1)/n(S) = 1/8.
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Step-by-step explanation:
Here is the simplest demonstration: If you flip a coin three times, you're either going to get more heads or more tails. There is no other possibility. Assuming the coin is unbiased, a majority-heads result can be no more or less likely than a majority-tails result. Therefore the answer is 1/2.
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