Question

Probability of having 5 sundays and 5 mondays in february month a leap year

Answer 1

5/29 & 5/29 Monday and Tuesday respectively.

Answer 2

Given: February month a leap year.

To find: The probability of having 5 sundays and 5 mondays in february month a leap year.

Solution: The probability of having 5 Sundays and 5 Mondays in February month a leap year is 1/49.

In a leap year, there are 29 days in February. Each week has a Sunday and a Monday. Also, every week has 7 days. Now, a month must have 4 complete weeks. Hence,

$7*4=28 days$

Thus, 4 Mondays and 4 Sundays are fixed. Now, the number of days left is

$29 - 28 = 1$

This day could be any of the 7 of the days. If the day is Sunday then the probability of having 5 Sundays would be

$P(S) = \frac{1}{7}$

Similarly, if the day is Monday then the probability of having 5 Mondays would be

$P(M) = \frac{1}{7}$

Thus, the probability of having both 5 Sundays and 5 Mondays is

$P(E) = \frac{1}{7} *\frac{1}{7}$

         $= \frac{1}{49}$

Therefore, the probability of having 5 Sundays and 5 Mondays in February month a leap year is 1/49.