Probability of having 53 Sundays in a leap year
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Solution :
A leap year contains 366 days .
A leap year contains 366/7 = 52 weeks and 2 days
These two days can be combination of
1. Saturday and Sunday
2. Sunday and Monday
3. Monday and Tuesday
4. Tuesday and Wednesday
5. Wednesday and Thursday
6. Thursday and Friday
7. Friday and Saturday
Since Leap year contains 52 weeks and 2 days ,
Each week contains 1 sunday , and probability of sunday for 2 days = 2/7
( 1. Saturday and Sunday
2. Sunday and Monday)
Therefore Probability of having Sunday in a leap year = 52 + 2/7
= 7*52 +2/7
=364+2/7
= 366/7
Hope this helps You .
Thank You .
Kindly let me know if you have any issues.
Cheers !!
A leap year contains 366 days .
A leap year contains 366/7 = 52 weeks and 2 days
These two days can be combination of
1. Saturday and Sunday
2. Sunday and Monday
3. Monday and Tuesday
4. Tuesday and Wednesday
5. Wednesday and Thursday
6. Thursday and Friday
7. Friday and Saturday
Since Leap year contains 52 weeks and 2 days ,
Each week contains 1 sunday , and probability of sunday for 2 days = 2/7
( 1. Saturday and Sunday
2. Sunday and Monday)
Therefore Probability of having Sunday in a leap year = 52 + 2/7
= 7*52 +2/7
=364+2/7
= 366/7
Hope this helps You .
Thank You .
Kindly let me know if you have any issues.
Cheers !!
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