probability of leap year having 53 Sundays is
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34
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4
Answer:
We know that there are 366 days in a leap year = 52 weeks + 2 days.
These 2 days can be:
1. {Sun, mon}
2. {Mon, Tues}
3. {Tues, Wed}
4. {Wed, Thurs}
5. {Thurs, Fri}
6. {Fri, Sat}
7. {Sat, Sun}
n(s) = 7.
Now,
Out of these 7 outcomes, the favorable outcomes are 2.(Sun, mon),(Sat, Sun).
n(a) = 2.
Therefore the required probability p(A) = n(A)/n(S)
= 2/7.
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