Probability of not getting any tail on tossing two coins simultaneously is
Answers
Answer:
For any individual toss of the coin, the outcome will be either heads or tails. The two outcomes (heads or tails) are therefore mututally exclusive; if the coin comes up heads on a single toss, it cannot come up tails on the same toss. ... The probability of getting two heads on two coin tosses is 0.5 x 0.5 or 0.25.
Step-by-step explanation:
When two different coins are tossed simultaneously, the sample space is given by
S={HH,HT,TH,TT}
Therefore, n(S)=4.
(1) Getting two heads:
Let E
1
be an event of getting 2 heads.
Then, E
1
={HH} and, therefore, n(E
1
)=1.
Therefore, P(getting 2 heads) =P(E
1
)=
n(S)
n(E
1
)
=
4
1
.
(2) Getting one tail:
Let E
2
= event of getting 1 tail. Then,
E
2
={TH,HT} and, therefore, n(E
2
)=2.
Therefore, P(getting 1 tail) =P(E
2
)=
n(S)
n(E
2
)
=
4
2
=0.5
(3) Getting no tail:
Let E
3
= event of getting no tail. Then,
E
3
={HH} and, therefore, n(E
3
)=1.
Therefore, P(getting no tail) =P(E
3
)=
n(S)
n(E
3
)
=
4
1