Probability of obtaining genotype AABbCc in the cross between AaBbCc *AaBbCc is the problem
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as 3 heterozygous genes are crossed .. so total possible zygotes will be 4 raised to 3
as 3 heterozygous genes are crossed .. so total possible zygotes will be 4 raised to 3
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2
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Ans is 1/16.
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