Probability of one of the power plants over heating is 0.15 per day and the probability of failure of back cooling system is 0.11. If these events are independent, what is the probability of ‘big trouble' (i.E. Both events taking place)?
Answers
Answered by
14
Hey,
Probability of power plant over heating is=0.15.
Probability of failure of backup cooling system is=0.11.
Probability of Big Problem is=Backup cooling system fails as well as power plant over heating
=(0.15) *(0.11)
=0.0165 ANSWER
HOPE IT HELPS YOU:-))
Probability of power plant over heating is=0.15.
Probability of failure of backup cooling system is=0.11.
Probability of Big Problem is=Backup cooling system fails as well as power plant over heating
=(0.15) *(0.11)
=0.0165 ANSWER
HOPE IT HELPS YOU:-))
Answered by
5
Answer:
The probability will be 0.0165
Step-by-step explanation:
Given
Probability of power plant over heating P( H ) = 0.15
Probability of failure of backup cooling system is P( C ) = 0.11
According to question,
These events are independent,
So
The probability of Big Problem will be that Backup cooling system fails as well as power plant over heating, that is,
P( H ) * P( C )
= ( 0.15 ) * ( 0.11 )
= 0.0165
Hence,
The probability will be 0.0165
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