Probability of taking alternate balls of
red and blue balls is 308/4845. 4 balls
are drawn one by one and not
replaced. If there are 12 red balls and
total number of balls is 20, which of the
following can be found?
A) Probability of taking both red balls
B) Probability of taking one blue ball
Probability of taking I ball
Answers
Answer:
There are 8 blue balls
Step-by-step explanation:
Given,
The probability of taking alternate balls of red and blue balls =308/4845
The total red balls = 12
Total number of balls = 20
To Find,
Which of the following can be found?
A) Probability of taking both red balls
B) Probability of taking one blue ball
C) Probability of taking 1 ball
Solution,
The total number of balls = 20 = The number of red and blue balls
20 = 12 + The number of blue balls
The number of blue balls = 20 - 12
The number of blue balls = 8
The probability of taking both red balls = 12/20*11/19
The probability of taking both red balls = 33/95
The probability of taking one blue ball = 8/20
The probability of taking one blue ball = 2/5
The probability of taking 1 ball = 1 [Sure event]
Hence, the probability of taking both red balls and taking one blue ball and taking 1 ball can be found.