Question

probability probability of an event E+ probability of the event 'not e'​

Answer 1

1

Question :

what is the probability of event E + event not E

Answer :

maximum of probability of any event is 1. hence the sum of probability of event E and event not E must be 1

Verification :

A die is threw what will be the probability of getting odd number + not getting odd number

$probability = \frac{favorable \: outcome}{sample \: space}$

Sample space = { 1,2,3,4,5,6 }

Let A be geeing an odd number and B be not getting an odd number. ( not an odd number must be a even number )

A = { 1,3,5 )

n(A) = 3

B = { 2,4,6 }

n(B) = 3

$probability \: of \: getting \: odd \: number \: = \frac{n(A)}{n(S)} \\ = \frac{3}{6} \\ = \frac{1}{2} </p><p>$

$probability \: of \: not \: getting \: odd \: number = \frac{n(B)}{n(S) } \\ = \frac{3}{6} \\ = \frac{1}{2}$

probability of getting odd number + not getting odd number = $\frac{1}{2}+\frac{1}{2}$

$\frac{1 + 1}{2} = \frac{2}{2} = 1$