Question

Probability randome number picker with lower prob of higher number

Answer 1

Step-by-step explanation:

1. Just thinking: another possibility is to get rid of the fractions by multiplying with a constant multiplier, and then build an array with the size of this multiplier. Multiplying by 10 you get
3. P(1) = 2
4. P(2) = 3
5. P(3) = 5
6. Then you create an array with the inverse values -- '1' goes into elements 1 and 2, '2' into 3 to 6, and so on:
8. P = (1,1, 2,2,2, 3,3,3,3,3);
10. and then you can pick a random element from this array instead.