Question

probability... solve this question properly with solution answeet is 1/2 .. solve it​

Answer 1

Step-by-step explanation:

Given that, P(A∩B) = 1/6 and P(A’∩B’)= ⅓

Given that, P(A∩B) = 1/6 and P(A’∩B’)= ⅓As, A and B are independent events,

Given that, P(A∩B) = 1/6 and P(A’∩B’)= ⅓As, A and B are independent events,P(A∩B) = P(A).P(B) = ⅙

Given that, P(A∩B) = 1/6 and P(A’∩B’)= ⅓As, A and B are independent events,P(A∩B) = P(A).P(B) = ⅙P(A’∩B’) = P(A’).P(B’) = ⅓

Given that, P(A∩B) = 1/6 and P(A’∩B’)= ⅓As, A and B are independent events,P(A∩B) = P(A).P(B) = ⅙P(A’∩B’) = P(A’).P(B’) = ⅓[1-P(A)][1-P(B)] = 1/3

Given that, P(A∩B) = 1/6 and P(A’∩B’)= ⅓As, A and B are independent events,P(A∩B) = P(A).P(B) = ⅙P(A’∩B’) = P(A’).P(B’) = ⅓[1-P(A)][1-P(B)] = 1/3Let P(A) = X and P(B) = y

Given that, P(A∩B) = 1/6 and P(A’∩B’)= ⅓As, A and B are independent events,P(A∩B) = P(A).P(B) = ⅙P(A’∩B’) = P(A’).P(B’) = ⅓[1-P(A)][1-P(B)] = 1/3Let P(A) = X and P(B) = yTherefore, we get,

Given that, P(A∩B) = 1/6 and P(A’∩B’)= ⅓As, A and B are independent events,P(A∩B) = P(A).P(B) = ⅙P(A’∩B’) = P(A’).P(B’) = ⅓[1-P(A)][1-P(B)] = 1/3Let P(A) = X and P(B) = yTherefore, we get,xy = ⅙, adn (1-x)(1-y) = ⅓

Given that, P(A∩B) = 1/6 and P(A’∩B’)= ⅓As, A and B are independent events,P(A∩B) = P(A).P(B) = ⅙P(A’∩B’) = P(A’).P(B’) = ⅓[1-P(A)][1-P(B)] = 1/3Let P(A) = X and P(B) = yTherefore, we get,xy = ⅙, adn (1-x)(1-y) = ⅓Solve the above two equations,

we get x= P(A) = ½

Answer 2

Answer:

The probability that both A and B occur together is 1/6 and the probability that either of them occurs is 1/3. The probability of occurrence of A is. x= P(A) = ½ or ⅓.

Step-by-step explanation:

pls mark me the brainlist