Question

probability that 4th power of positive integer ends in digit 6 is​

Answer 1

Step-by-step explanation:

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pas-1111

I'd=9813205349

Answer 2

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The final digit of any power of an integer relies solely on the final digit of the original integer itself.

We have the following:

Original Last Digit

0

1

2

3

4

5

6

7

8

9

last digit of the 4th power

0

1

6

1

6

5

6

1

6

1

Since each final digit of the original integer is equally likely, the probability that the fourth power of a randomly selected integer being 6 will be

$\frac{of \: choices \: that \: lead \: to \: final \: digit \: being6}{of \: choices \: regradless} = \frac{4}{10} = 40\%$

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