Probability that a bolt is defective is 10% .What is the chance that at of 5 b.1b selected exactly 3 are defective
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Answer:
x = bolt manufactured by company A.
y = bolt manufactured by company B.
z = bolt manufactured by company C.
w = defective bolt drawn.
P(x)=
10
3
,P(y)=
2
1
,P(z)=
5
1
P(w∣x)=
100
3
,P(w∣y)=
100
4
,P(w∣z)=
100
1
Probability that defective bolt is drawn from machine B.
P(y∣w)=
P(x).P(w∣x)+P(y).P(w∣y)+P(z).P(w∣z)
P(y).P(w∣y)
P(y∣w)=
31
20
Probability that it is not manufactured by B =1−
31
20
=
31
11
.
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