Question

Probable velocity of O2 at STP

Answer 1

Answer:

Probable velocity of O₂ at STP is 22.8 ms⁻¹

Explanation:

We know,

Most probable velocity, $c_{m p} = \sqrt{\frac{2RT}{M} }$

where,

R = universal gas constant = 8.314 J K⁻¹ mol⁻¹ = 8.314 × 10³ g m² s⁻² J K⁻¹mol⁻¹

T = temperature = 0°C = 273 K

M = molar mass of O₂ = 32 g mol⁻¹

∴ $c_{m p} = \sqrt[2]{\frac{(2)(8.314)(10^{3} )}{32} }$$m s^{-1}$

⇒ $c_{m p} = 22.8 m s^{-1}$