Probe that root 3 × root 5 is irrational
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Answer:
Let √3.√5 be rational.
√3.√5=a/b (a,b are co primes, integers)
Squaring,
{√3.√5}^2=(a/b)^2
(√15)^2=a^2/b^2
15=a^2/b^2
15=(a/b)^2
√15=a/b
But we know that √15 is irrational. But RHS is rationol.
Therefore our assumption is contradicted.
So,√3.√5 is irrational.
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